Rust Error E0063: missing struct field

What does E0063 mean?

Rust error E0063 occurs when not initializing all fields of a struct. This is a compile-time error that prevents potentially unsafe or incorrect code from running.

Broken Code

// This will cause error E0063
struct Point { x: i32, y: i32 }
let p = Point { x: 1 };

Why This Happens

The Rust compiler performs strict checks on ownership, borrowing, lifetimes, and types at compile time. When it reports E0063, it is preventing code that could lead to:

• Use-after-free bugs (dangling references)
• Data races (concurrent unsynchronized access)
• Type confusion (mixing incompatible types)
• Undefined behavior (violating Rust's safety guarantees)

How to Fix E0063

The fix is to provide all required fields or use ..Default::default().

// Fixed version
struct Point { x: i32, y: i32 }
let p = Point { x: 1, y: 2 };

Step-by-Step Debugging

1. Read the full error message — the compiler usually points to the exact line

2. Check the "note" lines — they often explain the root cause

3. Trace ownership flow — find where the value is created, moved, and used

4. Decide on the fix — borrow, clone, restructure, or change types

FAQ

Is E0063 a runtime error?

No. E0063 is a compile-time error. The program will not run until the issue is fixed.

Should I always use .clone() to fix this?

Not necessarily. While clone() can work, it may not be the most efficient solution. Consider borrowing, restructuring ownership, or using references instead.

Why is Rust so strict about this?

Rust guarantees memory safety without a garbage collector. The strict rules prevent entire classes of bugs at compile time, making your code more reliable.

Related Errors

See other common Rust errors in the error reference.